5x^2-12x-161=0

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Solution for 5x^2-12x-161=0 equation:


Simplifying
5x2 + -12x + -161 = 0

Reorder the terms:
-161 + -12x + 5x2 = 0

Solving
-161 + -12x + 5x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-23 + -5x)(7 + -1x) = 0

Subproblem 1

Set the factor '(-23 + -5x)' equal to zero and attempt to solve: Simplifying -23 + -5x = 0 Solving -23 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '23' to each side of the equation. -23 + 23 + -5x = 0 + 23 Combine like terms: -23 + 23 = 0 0 + -5x = 0 + 23 -5x = 0 + 23 Combine like terms: 0 + 23 = 23 -5x = 23 Divide each side by '-5'. x = -4.6 Simplifying x = -4.6

Subproblem 2

Set the factor '(7 + -1x)' equal to zero and attempt to solve: Simplifying 7 + -1x = 0 Solving 7 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1x = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1x = 0 + -7 -1x = 0 + -7 Combine like terms: 0 + -7 = -7 -1x = -7 Divide each side by '-1'. x = 7 Simplifying x = 7

Solution

x = {-4.6, 7}

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